00:01
You high students let me explain you the question here so in in this particular question we have to standardize a solution of nah oh h this solution of nahoh is having the concentration 0 .2 molar here we are using the primary standard is potassium hydrogen thalate so it having the molar must do 0 .2 gram per mole so here here we have to determine the mass of potassium hydrogen pallet, it utilized 20 ml, naoh titrant.
00:40
So this is the question.
00:42
These are the, so this is the table.
00:45
So this particular table, it is standardization.
00:49
So during the standardization of 0 .2 molar naoh titrent.
00:54
Then this is the standardization of 0 .2 molar titterent.
01:00
So this table it is standardization of 0 .2 molar titrate that is using calorimetric indicator.
01:14
So here coming to the solution, so here the reaction.
01:23
So this is the potassium hydrogen thallate.
01:28
So potassium hydrogen c .o .o.
01:33
N .a.
01:34
And o minus.
01:38
A plus plus water this is the reaction so here the concentration of n aoha concentration of n a o h point two molar volume so volume of n a o h it is utilized that is 20 m l and milly moles of n a oh h so how to find milly modes of n a o h that is molarity into volume volume we have to take in m l so that is molarity 0 .2 molar into 20 so that is equal to that is equal to 4 millimoles 4 millie moles to be utilized to be utilized so from the reaction so that is milly moles of milly moles reacted n .a.
02:32
Ohh that is equal to milly moles of ahp required potassium hydrogen thallate required so that is an millimoles of khp so millimoles of khp that is equal to 4 millimoles of milly moles of khp because we know that millimoles of a reactor de novoh it is 4 millimoles even millimals of khp it is equal to 4 millimoles that means uh moles of khp that is equal to 4 into 10 to power of minus 3 moles so molar mass of hb, so molar mass of hb, that is 204 .2 gram per molar...