00:01
So here we are given mean 2 equal to 73 standard variation to 8.
00:06
And for part a, we are to find the probability of x less than 93, which will be the probability of x minus mean over segment, it's less than 93 minus 73 over 8.
00:21
So we get probability of z less than 2 .5, which gives 0 .99 -38.
00:31
We have to find probability of x line between 65 and 89.
00:39
So this gives probability of 65 minus 73 over 8, which is less than x minus me over zina, it's less than 89 minus 73 on 8.
00:54
So we get probability of negative 1 .0 less than 2.
00:59
So we can write this as probability of z less than 2 .0 minus probability of z less than negative 1 .0, which gives us 0 .9 -772 minus 0 .1587.
01:20
So we get 0 .815.
01:28
For part c, we have to find the probability of x greater than small x is equal to 0 .05.
01:36
So this gives us 1 minus the probability of x less or equal to small x to be 0 .05.
01:44
So probability of x less or equal to small x will be equal to 1 minus 0 .05.
01:51
Which gives probability of x less or equal to small x to be 0 .95...