00:01
Hello, in this question we need to draw the structure of the benzaldehydehyde and also showing the reaction between these two.
00:09
So here, benzaldehyde, that means this molecule consists of one benzene ring and aldehyde, that means one aldehyde group it is attached to this.
00:22
So this molecule is the benzodiaide.
00:28
And here, that is methylylide.
00:34
Methylamine is c h3, this is methyl and to this amine group it is attached.
00:46
So this is methylamine.
00:48
So when they react with each other then they form the product here that is emine and here this is the benzene ring and to this in the place of oxygen we will have nitrogen and ch3 group it is attached and this is called as the emine.
01:16
If we see the mechanism here, so this benzine ring we have that is benzardydehyde double bond o it is there and this oxygen it is consisting of two lone pair of electron and here the ch3 and h2 it is there.
01:35
So this lone pair of electron which is present on the nitrogen it will attack at this carbon the more substituted carbon and hence the localization of electron will occur here and this will lead to the intermediate to this carbon here oxygen it is present with negative charge and to this nitrogen and here this hydrogen and hydrogen and h2 and this ch3 group it is present there so now and one hydrogen it is there now so here to this, this hydrogen molecule.
02:21
That means there will be the shifting of hydrogen here and hence it will lead to the formation of this to this carbon, oh group it is there and n, h and ch3 it is there and to this hydrogen it is attached...