00:01
Data represent the high temperature distribution for a summer month in a city from some of the last 130 years treat the data as a population so approximate the mean and standard deviation for temperature so what i had to do is i had to find the midpoint of each one so this one's 54 .5 64 .5 84 .5 84 .5 84 .5 94 .5 and 104 .5 and 104 .5.
00:30
Then i had to multiply it by the number of days.
00:37
And for 54 .5, i got obviously 54 .5.
00:43
This one i got 20 ,575.
00:48
This one, 109 ,813.
00:53
When i multiplied that by 1 ,513, i got 127 ,8848 .5.
01:00
This one was 49 ,000.
01:02
234 .5 and this one was 1 ,254.
01:07
When i totaled up all of these numbers, i got 3, 112 ,620...