3. The following data were collected from a repeated-measures study. Perform an ANOVA. Use the .05 level of significance for both. (10 POINTS) Treatment A B G = 36 2 6 ?X² = 192 4 4 4 8 T = 12 T = 24 SS = 4 SS = 8 1) State the null hypothesis 2) calculate necessary statistics (USE AN ANOVA even though K=2) ? = .05. 3) make a decision about your null hypothesis and explain what that decision means 4) Make a conclusion about your IV and DV that includes an APA format summary of your statistical analysis 4. With k = 2 treatments, are post hoc tests necessary when the null hypothesis is rejected? Explain your reasoning [5 Points] 5. Compare and contrast standard deviation and standard error of the mean [3 Points] 6. What is an outlier? How would you scan for outliers in your dataset? What would you do with data points that are considered outliers? [6 Points] 7. Big picture question: Now that you understand statistics. I want you to answer a couple of questions. Can a skilled statistician "make anything significant"? How would this be/not be accomplished? How could you design a study to guarantee significance? What is statistical power and how is it relevant to this big picture question? [6 Points]
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In this case, it would be: "There is no significant difference between the means of Group 1 and Group 2." Show more…
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Problem Set 4.4: One-way ANOVA Results in APA Style Criterion: Report ANOVA results in APA format. Data: Use the results from Problem Set 4.4. Instructions: Complete the following: State the null hypothesis and report your results in APA format (as you might see them reported in a journal article). We want to test hypothesis 1: The average for all treatments are the same vs. the average for at least one treatment is different than the others. Level= High, Moderate, Low Given the following information: Stress Levels High: 10, 7, 8, 12 Moderate: 9, 4, 7, 6 Low: 9, 4, 6, 5
Supreeta N.
ANOVA. i need a step by step tutorial on this question, excel is preferred when generating the ANOVA tables
Paul A.
When only two treatments are involved, ANOVA and the Student’s t test (Chapter 11) result in the same conclusions. Also, for computed test statistics, t2 = F. To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in a history course were divided into two groups, one consisting of 6 students who took the course in the normal lecture format. The other group of 8 students took the course as a distance course format. At the end of the course, each group was examined with a 50-item test. The following is a list of the number correct for each of the two groups. Traditional Lecture Distance 45 42 35 38 45 42 36 44 43 40 38 46 42 44 1= Complete the ANOVA table. (Round your SS, MS, and F values to 2 decimal places and p value to 4 decimal places.)? 2=a-2. Use a α = 0.01 level of significance. (Round your answer to 2 decimal places.) Using the t test from Chapter 11, compute t. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) There is any difference in the mean test scores.
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