Question

8) The following equations help calculate the resistivity of capacitors and inductors. For a coil, $X_L = \omega L = 2\pi fL$, and for capacitors $X_C = \frac{1}{\omega C} = \frac{1}{2\pi fC}$. Thus, the overall inductance can be calculated using: $Z = \sqrt{R^2 + (X_L - X_C)^2}$ (1) Suppose that the AC supply frequency is 120 Hz, R = 10 ?, L = 108 mH, and C = 0.10 F. Calculate the Z (impedance) of the system. (10 pts)

          8) The following equations help calculate the resistivity of capacitors and inductors. For a coil, $X_L = \omega L = 2\pi fL$, and for capacitors $X_C = \frac{1}{\omega C} = \frac{1}{2\pi fC}$. Thus, the overall inductance can be calculated using:
$Z = \sqrt{R^2 + (X_L - X_C)^2}$ (1)
Suppose that the AC supply frequency is 120 Hz, R = 10 ?, L = 108 mH, and C = 0.10 F. Calculate the Z (impedance) of the system. (10 pts)

8) The following equations help calculate the resistivity of capacitors and inductors. For a coil, XL = ω L = 2π fL, and for capacitors XC = (1)/(ω C) = (1)/(2π fC). Thus, the overall inductance can be calculated using:
Z = √(R^2 + (XL - XC)^2) (1)
Suppose that the AC supply frequency is 120 Hz, R = 10 ?, L = 108 mH, and C = 0.10 F. Calculate the Z (impedance) of the system. (10 pts)

Added by Michael A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Jagjit Singh Chander

12/19/2021

Step 1

x_(L) = 2πfL = 2π*120*108*10^(-3) = 81.6Ω x_(C) = (1)/(2πfC) = (1)/(2π*120*0.10) = 13.3Ω Show more…

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The following equations help calculate the resistivity of capacitors and inductors. For a coil, x_(L)=omega L=2pi fL, and for capacitors x_(C)=(1)/(omega )C= (1)/(2)pi fC. Thus, the overall inductance can be calculated using: Z=sqrt{R^{2}+(x_(L)-x_(C))^{2}} Suppose that the AC supply frequency is 120Hz, R=10Omega, L=108mH, and C=0.10F. Calculate the Z (impedance) of the system. (10 pts)