Question

The following figure represents a disk of mass $m$ connected to a spring and a box of mass $m$ via a massless string. The Lagrange's equation of motion is, (a) $\ddot{\theta} - \left(\frac{g}{b}\right) + \left(\frac{k}{m}\right)\theta = 0$ (b) $\ddot{\theta} - \frac{3}{2}\left(\frac{g}{b}\right) + \frac{3}{2}\left(\frac{k}{m}\right)\theta = 0$ (c) $\ddot{\theta} + \left(\frac{g}{b}\right) + \left(\frac{k}{m}\right)\theta = 0$ (d) $\ddot{\theta} - \frac{2}{3}\left(\frac{g}{b}\right) + \frac{2}{3}\left(\frac{k}{m}\right)\theta = 0$

          The following figure represents a disk of mass $m$ connected to a spring and a box of mass $m$ via a massless string.
The Lagrange's equation of motion is,
(a) $\ddot{\theta} - \left(\frac{g}{b}\right) + \left(\frac{k}{m}\right)\theta = 0$
(b) $\ddot{\theta} - \frac{3}{2}\left(\frac{g}{b}\right) + \frac{3}{2}\left(\frac{k}{m}\right)\theta = 0$
(c) $\ddot{\theta} + \left(\frac{g}{b}\right) + \left(\frac{k}{m}\right)\theta = 0$
(d) $\ddot{\theta} - \frac{2}{3}\left(\frac{g}{b}\right) + \frac{2}{3}\left(\frac{k}{m}\right)\theta = 0$
        
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The following figure represents a disk of mass m connected to a spring and a box of mass m via a massless string.
The Lagrange's equation of motion is,
(a) θ̈ - ((g)/(b)) + ((k)/(m))θ = 0
(b) θ̈ - (3)/(2)((g)/(b)) + (3)/(2)((k)/(m))θ = 0
(c) θ̈ + ((g)/(b)) + ((k)/(m))θ = 0
(d) θ̈ - (2)/(3)((g)/(b)) + (2)/(3)((k)/(m))θ = 0

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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The following figure represents a disk of mass m connected to a spring and a box of mas m via a massless string. The Lagrange's equation of motion is, (a) heta ^(¨)-((g)/(b))+((k)/(m)) heta =0 (b) heta ^(¨)-(3)/(2)((g)/(b))+(3)/(2)((k)/(m)) heta =0 (c) heta ^(¨)+((g)/(b))+((k)/(m)) heta =0 (d) heta ^(¨)-(2)/(3)((g)/(b))+(2)/(3)((k)/(m)) heta =0 The following figure represents a disk of mass m connected to a spring and a box of ma m via a massless string The Lagrange's equation of motion is, (a) o =0 (b) 9 K =0 m + (c) o . =0 (d) o 60| |2 9=
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Transcript

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00:01 In this question we have given particles a and b which are connected by a string and mass of particle a it is given as 1 .5 kg, mass of particle b it is given as 4 .0 kg, the disc has a mass of mc let's say which is 5 .0 kg and we have k which is a constant it is 500 n per meter which is a spring constant.
00:35 Now using this relation here we can write considering a, b and c as a system so let's say this is denoting the system if here we have point a, here we have point b and this is point c then here we have mass of c into g and in this direction we will have f cos of 37 degree plus mass of a plus mass of b multiplied by sin of 37 degree into g which is acceleration due to gravity...
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