Question

The following molecular equation represents the reaction that occurs when aqueous solutions of silver(I) nitrate and iron(III) bromide are combined. 3AgNO3(aq) + FeBr3(aq) ? 3AgBr(s) + Fe(NO3)3(aq) Write the balanced net ionic equation for the reaction. (Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.)

          The following molecular equation represents the reaction that occurs when aqueous solutions of silver(I) nitrate and iron(III) bromide are combined.

3AgNO3(aq) + FeBr3(aq) ? 3AgBr(s) + Fe(NO3)3(aq)

Write the balanced net ionic equation for the reaction.

(Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.)

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The following molecular equation represents the reaction that occurs when aqueous solutions of silver(I) nitrate and iron(III) bromide are combined.

3AgNO3(aq) + FeBr3(aq) ? 3AgBr(s) + Fe(NO3)3(aq)

Write the balanced net ionic equation for the reaction.

(Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.)

Added by Joy T.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Jennifer Hudspeth

11/15/2022

Step 1

Step 1:** Identify the ions present in the reaction: - Silver ion (Ag+) - Nitrate ion (NO3-) - Iron(III) ion (Fe3+) - Bromide ion (Br-) ** Show more…

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The following molecular equation represents the reaction that occurs when aqueous solutions of silver(I) nitrate and iron(III) bromide are combined. 3AgNO3(aq) + FeBr3(aq) → 3AgBr(s) + Fe(NO3)3(aq) Write the balanced net ionic equation for the reaction. (Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.)

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Transcript

00:02 Hi there.

00:03 In this question, we are given the balanced equation for this double replacement reaction.

00:07 In a double replacement reaction, the ions in the two ionic compounds exchange partners.

00:13 So the positive from the first goes with the negative from the second, and the positive from the second goes with the negative from the first.

00:19 In order to have a reaction, one of the new products must be insoluble.

00:23 And we see right here that that is the silver bromide.

00:27 It forms a precipitate.

00:29 All right.

00:29 What we want to write here then is the net.

00:32 Ionic equation.

00:40 The net ionic equation shows what combines to produce the reaction.

00:45 In other words, to produce the precipitate.

00:48 The net ionic equation omits the spectator ions.

00:54 The spectator ions are the ones that are the same on both sides of the equation.

00:59 So in other words, they're not doing anything.

01:00 They're just floating around watching what's going on, which is why they're called spectator ions.

01:07 All right, so let's identify our spectator ions.

01:10 Well, we see.

01:10 We see...

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