Question

senders Sender 1 data bits d1i = -1 d01 = 1 code 1 1 1 1 1 1 1 1 -1 -1 -1 -1 -1 -1 Z1i,m = d1i · c1m Sender 2 data bits d12 = 1 d02 = 1 code 1 1 1 1 1 1 1 1 1 1 1 1 -1 -1 -1 -1 -1 -1 Z2i,m = d2i · c2m channel, Zi,m* 2 2 2 2 2 2 -2 -2 d1i = ?m=1M Zi,m* · c1m / M slot 1 received input slot 0 received input d11 = -1 d01 = 1 receiver 1 code 1 1 1 1 1 1 1 1 -1 -1 -1 -1 -1 -1

          senders
Sender 1
data bits d1i = -1 d01 = 1
code 1 1 1 1 1 1 1 1
-1 -1 -1 -1 -1 -1
Z1i,m = d1i · c1m
Sender 2
data bits d12 = 1 d02 = 1
code 1 1 1 1 1 1 1 1 1 1 1 1
-1 -1 -1 -1 -1 -1
Z2i,m = d2i · c2m
channel, Zi,m*
2 2 2 2 2 2
-2 -2
d1i = ?m=1M Zi,m* · c1m / M
slot 1 received input slot 0 received input
d11 = -1 d01 = 1
receiver 1
code 1 1 1 1 1 1 1 1
-1 -1 -1 -1 -1 -1

senders
Sender 1
data bits d1i = -1 d01 = 1
code 1 1 1 1 1 1 1 1
-1 -1 -1 -1 -1 -1
Z1i,m = d1i · c1m
Sender 2
data bits d12 = 1 d02 = 1
code 1 1 1 1 1 1 1 1 1 1 1 1
-1 -1 -1 -1 -1 -1
Z2i,m = d2i · c2m
channel, Zi,m*
2 2 2 2 2 2
-2 -2
d1i = ?m=1M Zi,m* · c1m / M
slot 1 received input slot 0 received input
d11 = -1 d01 = 1
receiver 1
code 1 1 1 1 1 1 1 1
-1 -1 -1 -1 -1 -1

Added by Katherine M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

07/24/2024

Step 1

- Sender 1: Data bit \( d_1 = -1 \), Code \( c_1 = [-1, -1, 1, 1] \) - Sender 2: Data bit \( d_2 = 1 \), Code \( c_2 = [1, 1, 1, 1] \) Show more…

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The following picture is a copy of a Figure in the textbook. It shows a CDMA example that supports two senders. Suppose that the receiver wanted to receive the data being sent by sender 2. Show (by calculation) that the receiver is indeed able to recover sender 2's data from the aggregate channel signal by using sender 2's code.