00:01
In this problem we have been given a probability distribution which shows the probability of a car salesman selling x cars in a week.
00:09
So in this probability distribution table that has been given, x represents the number of cars sold in a week and px represents the probability of that many cars being sold in a week.
00:23
Now we need to use this probability distribution table to find certain probabilities.
00:29
Now, the full's question asks, what is the probability that the salesman sold exactly three cars? so if the salesman sold exactly three cars, we need to find p of three.
00:42
And from the table, we can see that that is 0 .26.
00:45
So the probability that the salesman sold exactly three cars will be 0 .26.
00:54
Next, we have been asked to find the probability that the salesman sold at least five cars.
01:00
So that means we need to find the probability that he sold at least five cars.
01:05
So that means numbers should be greater than five.
01:09
So if he sold at least five cars, then that means he either sold five cars or he sold six cars.
01:18
And that will end up being p5 plus p6.
01:23
We get this using the addition law of probability.
01:26
Now, p5 is 0 .11 and p6 is 0 .08.
01:31
We can obtain that from the table.
01:33
So we have 0 .11 plus 0 .08 and 0 .11 plus 0 .08 is equal to 0 .19.
01:45
So that is the required probability.
01:49
Next, we need to find the probability that the salesman sold at most two cars...