Question

The force acting on a particle varies as shown in the figure below. (The x axis in the graph has its tickmarks marked in increments of 0.50 m.) F_x (N) 6 B 4 2 A C E x (m) -2 D Find the work done by the force on the particle as it moves across the following distances. (a) from x = 0 m to x = 4.00 m J (b) from x = 4.00 m to x = 6.00 m J (c) from x = 0 m to x = 6.00 m J

          The force acting on a particle varies as shown in the figure below. (The x axis in the graph has its tickmarks marked in increments of 0.50 m.) F_x (N) 6 B 4 2 A C E x (m) -2 D Find the work done by the force on the particle as it moves across the following distances. (a) from x = 0 m to x = 4.00 m J (b) from x = 4.00 m to x = 6.00 m J (c) from x = 0 m to x = 6.00 m J
        
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The force acting on a particle varies as shown in the figure below. (The x axis in the graph has its tickmarks marked in increments of 0.50 m.) Fx (N) 6 B 4 2 A C E x (m) -2 D Find the work done by the force on the particle as it moves across the following distances. (a) from x = 0 m to x = 4.00 m J (b) from x = 4.00 m to x = 6.00 m J (c) from x = 0 m to x = 6.00 m J

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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The force acting on the particle varies as shown in the figure below. The axis of the graph has its tick marks marked in increments of 0.50 m. Find the work done by the force on the particle from x = 4.00 m to x = 6.00 m.
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Transcript

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00:01 In this question we are given a variable force on a particle and we are asked to find the work done by the force on the particle for a number of different displacements.
00:12 The key thing to remember for this question, what color would we like, how about pink, is that we can find work as the area on a force versus position graph.
00:31 Specifically, it's the area between the curve and horizontal axis, or we could say the x -axis.
00:45 And so for part a, to find the work done from 0 to 2 meters, so it told us that every line is 0 .25, so my tick marks here are at a half, 1, 1 .5, and then 2 .0 is out here at point c, so i need to find this area here.
01:19 For part a, well, swell, it's triangle, so that's going to be 1 half times the base times the height of this triangle.
01:31 My base is 2 .0 meters long and my height is up to point b, 6 newtons, and so i get 6 joules.
01:44 And if you want to keep the correct number of significant figures, you could even say 6 .0 joules...
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