00:01
So, students let us have a look on this question.
00:01
So, in this question we have given this diagram with moving with the force applied with the force f and the variable force we have given this graph also in the question we can see.
00:11
So, first of all i am applying here when the bloke is at rest what is happening here in this condition net work as rest we can say summation of f x is equal to 0 and we can say summation of f y is equal to 0.
00:25
So, from this condition i can say f y equal to 0 i can say n minus m g minus f 3 by 5 is equal to 0 this is equal to 0.
00:34
So, finally, i will get the normal is equal to m g plus f 3 by 5 this is the value of the normal force when it was at rest.
00:43
Now, when it start for sliding.
00:45
So, what i will get summation of f x is equal to m a x from a newton second law moving on this law what i can apply f 4 by 5 is equal to or we can say minus of f s is equal to m a x.
01:01
So, put the values here 4 by 5 minus of mu k f 3 by 5 then plus m g then finally, it will equal to m a x...