00:01
Hi, here in this given problem, variation between the force applied and the displacement of an object that is given as shown here.
00:16
The force has been taken over the y -axis and that is in newton, while the distance that is taken along x -axis and it is being measured in kilometer.
00:34
Distances over the x -axis these are 1 and 2 and 3 and 4 and 5 and 6 kilometers the force is 1 newton and 2 newton and in opposite direction this is minus 1 newton it is observed that the force first of all it goes on increasing linearly up to 2 newton at a distance of 2 meter, 2 km.
01:15
After that this force becomes constant up to 1 more kilometer, means up to 3 kilometer, then it drops to 0, force becomes 0.
01:27
Then no force will be being applied on the object up to 4 km.
01:33
After that the force starts increasing again but in opposite direction.
01:37
Up to a distance of 6 km and having the value of minus 1 newton here.
01:50
So in the first part of the problem we have to find work done on the object from x equals to 0 .0 to x equals to 3 .0 kilometer means this figure and here this figure include a triangle, right angle, triangle and a rectangle.
02:22
So this work done from 0 kilometer to 3 kilometer that will be equal to area, a1 plus area a2, area of triangle and area of this rectangle.
02:38
So here it will be for triangle.
02:41
This is half into base which is 2 kilometer or 2 ,000 meter into height which is 2 newton plus for the area of rectangle this is width.
02:57
For width means this is 3 minus 2 kilometer or into 1 ,000 meter into height which is 2 newton again...