Question

The Fraunhofer diffraction pattern for a single slit of width $a$ is given by: $I_\theta = I_0 \left( \frac{\sin(\beta / 2)}{\beta / 2} \right)^2$ where $\beta = (2\pi a / \lambda) \sin \theta$. Calculate the fractional intensity $I_\theta / I_0$ of a diffraction pattern at a point on the viewing screen 1.50 mm from the central maximum if the screen is 1.30 m away from the 0.050 mm wide aperture. Assume monochromatic light of wavelength 546.1 nm illuminates the aperture. (3 marks)

          The Fraunhofer diffraction pattern for a single slit of width $a$ is given by:
$I_\theta = I_0 \left( \frac{\sin(\beta / 2)}{\beta / 2} \right)^2$
where $\beta = (2\pi a / \lambda) \sin \theta$. Calculate the fractional intensity $I_\theta / I_0$ of a diffraction
pattern at a point on the viewing screen 1.50 mm from the central maximum if the screen
is 1.30 m away from the 0.050 mm wide aperture. Assume monochromatic light of
wavelength 546.1 nm illuminates the aperture.
(3 marks)

$The Fraunhofer diffraction pattern for a single slit of width a is given by: Iθ = I0 ( (sin(β / 2))/(β / 2))^2 where β = (2π a / λ) sinθ. Calculate the fractional intensity Iθ / I0 of a diffraction pattern at a point on the viewing screen 1.50 mm from the central maximum if the screen is 1.30 m away from the 0.050 mm wide aperture. Assume monochromatic light of wavelength 546.1 nm illuminates the aperture. (3 marks)$

Added by William J.

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