Question

The free energy density change of mixing of a binary mixture is given by ∆𝑓 = B12∅1∅2 +𝑅𝑇((∅1/𝑣1)ln∅1 +(∅2/𝑣2)ln∅2 ). Where B12 , 𝑣𝑖 and ∅𝑖 are interaction energy density, molar volume of component i and volume fraction of component i, respectively. Derive the condition of equilibrium when 𝑣1 = 𝑣2. Assume that interaction energy does not depend on volume fraction.

Name: the free energy density change of mixing of a binary mixture is given by f b1212 rt1v1ln1 2v2ln2 where b12 vi and i are interaction energy density molar volume of component i and volume frac 11264
Uploaded: 2022-10-08T13:50:04-08:00
Duration: 2 min 56 s
Channel: Sri K
Description: the free energy density change of mixing of a binary mixture is given by f b1212 rt1v1ln1 2v2ln2 where b12 vi and i are interaction energy density molar volume of component i and volume frac 11264

          The free energy density change of mixing of a binary mixture is given by ∆𝑓 = B12∅1∅2 +𝑅𝑇((∅1/𝑣1)ln∅1 +(∅2/𝑣2)ln∅2 ). Where B12 , 𝑣𝑖 and ∅𝑖 are interaction energy density, molar volume of component i and volume fraction of component i, respectively. Derive the condition of equilibrium when 𝑣1 = 𝑣2. Assume that interaction energy does not depend on volume fraction.

Added by Nicholas T.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

10/08/2022

Step 1

Step 1: Start with the expression for the free energy density change of mixing, ∆𝑓 = B12∅1∅2 +𝑅𝑇((∅1/𝑣1)ln∅1 +(∅2/𝑣2)ln∅2 ). Show more…

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The free energy density change of mixing of a binary mixture is given by ∆𝑓 = B12∅1∅2 +𝑅𝑇((∅1/𝑣1)ln∅1 +(∅2/𝑣2)ln∅2 ). Where B12 , 𝑣𝑖 and ∅𝑖 are interaction energy density, molar volume of component i and volume fraction of component i, respectively. Derive the condition of equilibrium when 𝑣1 = 𝑣2. Assume that interaction energy does not depend on volume fraction.