Question

The full width at half maximum of an atomic absorption line at 589.0 nm is 100 MHz. A beam of light passes through a gas with an atomic density of 1x10 17 m-3 . Calculate: a) The peak absorption coefficient due to this absorption line Hint: n can be assumed to about 1 because it is gas. b) The frequency at which the resonant contribution to the refractive index is at a maximum c) The peak value of the resonant contribution to the refractive index

Name: the full width at half maximum of an atomic absorption line at 5890 nm is 100 mhz a beam of light passes through a gas with an atomic density of 1x10 17 m 3 calculate a the peak absorption c 26197
Uploaded: 2023-10-28T19:08:27-08:00
Duration: 2 min 39 s
Channel: Rachel Gore
Description: the full width at half maximum of an atomic absorption line at 5890 nm is 100 mhz a beam of light passes through a gas with an atomic density of 1x10 17 m 3 calculate a the peak absorption c 26197

          The full width at half maximum of an atomic absorption line at
589.0 nm is 100 MHz. A
beam of light passes through a gas with an atomic density of 1x10
17 m-3 . Calculate:
a) The peak absorption coefficient due to this absorption
line
Hint: n can be assumed to about 1 because it is gas.
b) The frequency at which the resonant contribution to the
refractive index is at a
maximum
c) The peak value of the resonant contribution to the refractive
index

the full width at half maximum of an atomic absorption line at 5890 nm is 100 mhz a beam of light passes through a gas with an atomic density of 1x10 17 m 3 calculate a the peak absorption c 26197

Added by David C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Rachel Gore

10/28/2023

Step 1

Given: λ = 589.0 nm = 589.0 * 10^-9 m n = 1x10^17 m^-3 γ = 100 MHz = 100 * 10^6 Hz c = 3 * 10^8 m/s Substituting the values into the formula: α = (π * (589.0 * 10^-9)^2 * (1x10^17) * (100 * 10^6)) / (2 * 3 * 10^8) Calculating the value: α ≈ 3.27 * 10^6 m^-1 Show more…

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The full width at half maximum of an atomic absorption line at 589.0 nm is 100 MHz. A beam of light passes through a gas with an atomic density of 1x10 17 m-3 . Calculate: a) The peak absorption coefficient due to this absorption line Hint: n can be assumed to about 1 because it is gas. b) The frequency at which the resonant contribution to the refractive index is at a maximum c) The peak value of the resonant contribution to the refractive index