Question

The function $f(x) = \sin (kx)$ contains the point $A(\pi, -1)$. The function is: a) $f(x) = \sin (-\frac{1}{2}x)$ b) $f(x) = \sin (\frac{1}{2}x)$ c) $f(x) = \sin (2x)$ d) $f(x) = \sin (-2x)$

Name: the function fx sin kx contains the point api 1 the function is a fx sin frac12x b fx sin frac12x c fx sin 2x d fx sin 2x 72283
Uploaded: 2021-06-26T00:37:05-08:00
Duration: 3 min 10 s
Channel: Andrija Isakov
Description: the function fx sin kx contains the point api 1 the function is a fx sin frac12x b fx sin frac12x c fx sin 2x d fx sin 2x 72283

          The function $f(x) = \sin (kx)$ contains the point $A(\pi, -1)$. The function is:
a) $f(x) = \sin (-\frac{1}{2}x)$
b) $f(x) = \sin (\frac{1}{2}x)$
c) $f(x) = \sin (2x)$
d) $f(x) = \sin (-2x)$

$the function fx sin kx contains the point api 1 the function is a fx sin frac12x b fx sin frac12x c fx sin 2x d fx sin 2x 72283$

Added by Elizabeth M.

Introductory and Intermediate Algebra for College Students 4th

Robert Blitzer 4th Edition

Instant Answer

Solved by Expert Andrija Isakov

06/26/2021

Step 1

This means that when $x = \pi$, $f(x) = -1$. We can substitute these values into the function equation. Step 2: Substitute $x = \pi$ and $f(x) = -1$ into the equation $f(x) = \sin(kx)$: $-1 = \sin(k\pi)$ Step 3: We need to find the value of $k$ such that Show more…

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The function $f(x) = \sin (kx)$ contains the point $A(\pi, -1)$. The function is: a) $f(x) = \sin (-\frac{1}{2}x)$ b) $f(x) = \sin (\frac{1}{2}x)$ c) $f(x) = \sin (2x)$ d) $f(x) = \sin (-2x)$