00:01
All right, here in problem 39, when we're looking at these two functions, well, i want to find the value of f of 5 minus 2 times g of 1.
00:06
Let's look at f of 5 first.
00:09
Now, all this tells you to do is go up to your function that's named f, and then plug 5 in for x.
00:15
So f of 5 is equal to 2 times 5.
00:21
Again, all you're doing is going up there to that f function, putting 5 in 5 for x.
00:24
You take 2 times 5, and it gives us 10.
00:28
All right, so f of 5 here became 10.
00:31
Now let's look at this other part.
00:32
Now, you've got that minus 2 out front, but let's just find g of 1 first.
00:38
So g of 1 tells you come up here to your g function, and then plug in 1 for x.
00:45
So this would be 1 squared plus 1...