The ΔG°' for the reaction below is -26 kJ/mol at 37°C. What is the Gibbs free energy change for the reaction if each reactant is 0.03 M and each product is 0.02 M in concentration? Use R = 8.31 J/mol-K. Give your answer in normal notation. A ↔ B + C
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Step 1
02)(0.02) / (0.03) = 0.0133 Now, we can use the equation ΔG = ΔG°' + RT ln(Q) to find the Gibbs free energy change for the reaction: ΔG = -26 kJ/mol + (8.31 J/mol-K)(310 K) ln(0.0133) Note that we need to convert ΔG°' to J/mol: Show more…
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