Question

The gas phase decomposition of dinitrogen pentoxide at 335 K: N2O5(g) → 2 NO2(g) + ½ O2(g) is first order in N2O5 with a rate constant of 4.70×10-3 s-1. If an experiment is performed in which the initial concentration of N2O5 is 8.15×10-2 M, what is the concentration of N2O5 after 364.0 s have passed? A. 3.81×10-2 M B. 6.37×10-2 M C. 3.07×10-2 M D. 1.47×10-2 M

Name: the gas phase decomposition of dinitrogen pentoxide at 335 k n2o5g 2 no2g 12 o2g is first order in n2o5 with a rate constant of 47010 3 s 1 if an experiment is performed in which the initial 32684
Uploaded: 2022-02-25T04:53:51-08:00
Duration: 3 min 45 s
Channel: Pravin N
Description: the gas phase decomposition of dinitrogen pentoxide at 335 k n2o5g 2 no2g 12 o2g is first order in n2o5 with a rate constant of 47010 3 s 1 if an experiment is performed in which the initial 32684

          The gas phase decomposition of dinitrogen pentoxide at 335 K:
N2O5(g) → 2 NO2(g) + ½ O2(g)
is first order in N2O5 with a rate constant of 4.70×10-3 s-1.
If an experiment is performed in which the initial concentration of N2O5 is 8.15×10-2 M, what is the concentration of N2O5 after 364.0 s have passed?

A. 3.81×10-2 M
B. 6.37×10-2 M
C. 3.07×10-2 M
D. 1.47×10-2 M

Added by Johnny M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Pravin N

02/25/2022

Step 1

Step 1: Use the integrated rate law for a first-order reaction, which is: \[ \ln \left( \frac{[N2O5]_{t}}{[N2O5]_{0}} \right) = -kt \] where: - \([N2O5]_{t}\) is the concentration of N2O5 at time \(t\) - \([N2O5]_{0}\) is the initial concentration of N2O5 - Show more…

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The gas phase decomposition of dinitrogen pentoxide at 335 K: N2O5(g) → 2 NO2(g) + ½ O2(g) is first order in N2O5 with a rate constant of 4.70×10-3 s-1. If an experiment is performed in which the initial concentration of N2O5 is 8.15×10-2 M, what is the concentration of N2O5 after 364.0 s have passed? A. 3.81×10-2 M B. 6.37×10-2 M C. 3.07×10-2 M D. 1.47×10-2 M