Question

The genome of E. coli has a molecular weight of 2.5 x 109 Da (Da stands for Dalton). 1. Knowing that the average molecular weight of a nucleotide is 300 Da, the distance between two adjacent nucleotides is 0.34 nm, and the number of base pairs per turn of helix is 10, you are asked to calculate. - The number of base pairs in the E. coli genome - The length of the E. coli genome - The number of helical turns in the genome 2. Calculate the number of proteins with an average molecular weight of 60,000 Da that are coded by the E. coli genome assuming that 80% of the E.coli genome contain open reading frames. Assume that the average molecular weight of an amino acid is 100 Da and that every amino acid is coded by 3 nucleotides, and each open reading frame ends by a stop codon (nucleotide triplet) that does not code for any amino acid.

          The genome of E. coli has a molecular weight of 2.5 x 109 Da (Da
stands for Dalton).
1. Knowing that the average molecular weight of a nucleotide is 300
Da, the distance between two adjacent nucleotides is 0.34 nm,
and the number of base pairs per turn of helix is 10, you are asked
to calculate.
- The number of base pairs in the E. coli genome
- The length of the E. coli genome
- The number of helical turns in the genome
2. Calculate the number of proteins with an average molecular
weight of 60,000 Da that are coded by the E. coli genome
assuming that 80% of the E.coli genome contain open reading frames.
Assume that the average molecular weight of an amino acid is
100 Da and that every amino acid is coded by 3 nucleotides, and
each open reading frame ends by a stop codon (nucleotide
triplet) that does not code for any amino acid.

Added by Cristian J.

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