00:01
Hello, here we have to solve the following problem.
00:03
And we have to, our task is to sketch displacement versus time and acceleration versus time.
00:11
But first, before we proceed to it, proceed to the solution, let's split this motion into three parts.
00:19
The first one is from zero seconds to six seconds.
00:26
So let's find acceleration here.
00:29
So acceleration one equals to 60 meters per second divided by six seconds which is 10 meters per second squared that's why displacement during this stage one as a function of time equals to zero or here that is basically y as a function of time equals to zero plus a 1 t squared over 2 which is 5 meter 5 t squared meters per second squared and y at the moment of 6 seconds equals to the following so that is 5 times 36 meters which is 180 meters okay, that is done.
01:44
Now let's look at the stage two.
01:46
Here is from six to eight seconds.
01:52
So here speed is constant, which is constantly 60 meters per second.
01:58
Therefore, acceleration is zero.
02:03
And the displacement can be written as falling.
02:08
So that equals to y equals to 100.
02:12
180 meters plus 60 times t minus 6 meters...