00:01
I think the main thing that's tricky about this problem is the units.
00:04
You are counting by twos on all of these.
00:08
So i don't think i'm going to write out all these values, but in order to be a max, it has to change from increasing to decreasing.
00:16
So you have a max here and then somewhere over here you have another max.
00:21
So just to go in order, oh, and that's the other thing is you probably shouldn't write out the parentheses because they provide the parentheses for you.
00:29
But i'm just trying to go in order while i count.
00:33
The first local max is at negative four, two, four, six, eight, 10, 12, 14, 16.
00:38
And then the next local max is over here at two, four, two, four, six.
00:47
So hopefully you're following along and seeing where i'm getting those numbers.
00:51
The first local min is at the bottom of the curve at that zero negative four.
00:59
Again, notice that we're counting by twos here...