The half-life of 218Po is 3.1 minutes. How much of a 155 gram sample remains after 0.40 hours? Given ln(Nt/No) = -kt ; k = 0.693 / t_1/2 0.72 g 0.072 g 0.00034 g 7.2 g 0.0067 g
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Given: half-life (t1/2) = 3.1 minutes We can use the formula k = 0.693/t1/2 to find the value of k. k = 0.693/3.1 = 0.2235 minutes^-1 Show more…
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