The heat of combustion of propane is -2.20E3 kJ/mol. Calculate the energy in kJ produced when 50.0 g of propane is burned in excess oxygen.
Added by Billy R.
Step 1
First, we need to find the number of moles of propane in 50.0 g. The molecular weight of propane (C3H8) is 3(12.01) + 8(1.01) = 44.11 g/mol. Show more…
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C3H8 + 5O2 -> 3CO2 + 4H2O The enthalpy of reaction is -2202.0 kJ/mol. How much energy (in joules) will be released if 96.20 grams of propane is burned? (Molar mass of propane: 44.11 g/mol)
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The combustion of propane is described by the following equation: C3H8 (g) + 5O2 (g) -> 3CO2 (g) + 4H2O (l) ΔHrxn = -2220 kJ. Calculate the mass of propane that must be burned to obtain 350 kJ of heat.
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