Question

The heat of solution of ammonium chloride is 15.2 kJ/mol. If a 6.495 g sample of NH4Cl is added to 65.0 mL of water in a calorimeter at 26.9°C, what is the minimum temperature reached by the solution? [specific heat of water = 4.18 J/g•°C; heat capacity of the calorimeter = 365 J/°C]

Name: the heat of solution of ammonium chloride is 152 kjmol if a 6495 g sample of nh4cl is added to 650 ml of water in a calorimeter at 269c what is the minimum temperature reached by the solutio 93024
Uploaded: 2023-09-12T12:13:00-08:00
Duration: 5 min 25 s
Channel: Susan Hallstrom
Description: the heat of solution of ammonium chloride is 152 kjmol if a 6495 g sample of nh4cl is added to 650 ml of water in a calorimeter at 269c what is the minimum temperature reached by the solutio 93024

          The heat of solution of ammonium chloride is 15.2 kJ/mol. If a 6.495 g sample of NH4Cl is added to 65.0 mL of water in a calorimeter at 26.9°C, what is the minimum temperature reached by the solution? [specific heat of water = 4.18 J/g•°C; heat capacity of the calorimeter = 365 J/°C]

Added by Amber R.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Susan Hallstrom

09/12/2023

Step 1

First, we need to find the moles of NH4Cl in the 6.495 g sample. The molar mass of NH4Cl is (14.01 + 4*1.01 + 35.45) g/mol = 53.49 g/mol. So, the moles of NH4Cl are: moles = (6.495 g) / (53.49 g/mol) = 0.1214 mol Show more…

Show all steps

Thanks for your feedback!

The heat of solution of ammonium chloride is 15.2 kJ/mol. If a 6.495 g sample of NH4Cl is added to 65.0 mL of water in a calorimeter at 26.9°C, what is the minimum temperature reached by the solution? [specific heat of water = 4.18 J/g•°C; heat capacity of the calorimeter = 365 J/°C]