00:01
Hi, so to solve for this we will use this formula.
00:06
The change in entropy, delta s is equivalent to the enthalpy of vaporization in terms of kilojoules over the boiling point of the substance.
00:17
So let's calculate first delta h of vaporization, delta h of vaporization.
00:23
If we have 23 .4 kilojoules per mole and then we'll multiply the amount of ammonia, we have 629 grams.
00:34
We need to convert this to moles so that we could cancel out moles in the given delta h.
00:39
So molar mass of ammonia is, let's write first the formula for ammonia.
00:46
Ammonia is nh3.
00:48
Convert this to moles by dividing the molar mass of nh3.
00:54
Ammonia 17 .04 grams.
00:56
We have here moles so that means we could cancel grams of nh3 and then moles and our remaining unit will be kilojoules...