The height of a projectile fired straight up in the air with an initial velocity of 64 ft/s is given by the equation h = 64t - 16t^2, where h represents the height in feet and t represents the time in seconds. The table below represents the data for another projectile. a. Which projectile goes higher? How much higher? b. At what times t will each projectile be at a height of 16 feet? Table: Time Height 0.5 20 1 32 1.5 36 2 32
Added by Kevin W.
Step 1
To determine which projectile goes higher, we need to compare the maximum height reached by each projectile. The equation for the height of the first projectile is h = 64t - 16t^2. This is a quadratic equation, and we know that the maximum height occurs at the Show more…
Show all steps
Close
Your feedback will help us improve your experience
Supreeta N and 62 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Projectile The height in feet of a projectile with an initial velocity of 64 feet per second and an initial height of 80 feet is a function of time $t$ in seconds given by $$ h(t)=-16 t^{2}+64 t+80 $$ a. Find the maximum height of the projectile. b. Find the time $t$ when the projectile achieves its maximum height. c. Find the time $t$ when the projectile has a height of 0 feet.
Tyna S.
Functions and Graphs
Quadratic Functions
The height of a projectile launched upward at a speed of 32 feet/second from a height of 128 feet is given by the function $h(t)=-16 t_{2}+32 t+128 .$ a. What is the height of the projectile at $1 / 2$ second? b. At what time after launch will the projectile reach a height of 128 feet?
Solving Quadratic Equations and Graphing Parabolas
Guidelines for Solving Quadratic Equations and Applications
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD