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The heights of 18-year-old men are approximately normally distributed with mean of 68 inches and standard deviation of 3 inches. PART 1: What is the probability that an 18-year-old man selected at random is between 67 and 71 inches tall? Round to 4 decimal places. PART 2: For a sample of 36 18-year-old men, what is the probability that the average of their heights is between 67 and 71 inches? Round to 4 decimal places. PART 3: What sample n would be necessary in order to have P(67 < x? < 69) = 0.95 Round to the nearest whole number.

          The heights of 18-year-old men are approximately normally distributed with mean of 68 inches and standard deviation of 3 inches.
PART 1: What is the probability that an 18-year-old man selected at random is between 67 and 71 inches tall?
Round to 4 decimal places.
PART 2: For a sample of 36 18-year-old men, what is the probability that the average of their heights is between 67 and 71 inches?
Round to 4 decimal places.
PART 3: What sample n would be necessary in order to have P(67 < x? < 69) = 0.95
Round to the nearest whole number.
        
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The heights of 18-year-old men are approximately normally distributed with mean of 68 inches and standard deviation of 3 inches.
PART 1: What is the probability that an 18-year-old man selected at random is between 67 and 71 inches tall?
Round to 4 decimal places.
PART 2: For a sample of 36 18-year-old men, what is the probability that the average of their heights is between 67 and 71 inches?
Round to 4 decimal places.
PART 3: What sample n would be necessary in order to have P(67 < x? < 69) = 0.95
Round to the nearest whole number.

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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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The heights of 18-year-old men are approximately normally distributed with mean of 68 inches and standard deviation of 3 inches. PART 1: What is the probability that an 18-year-old man selected at random is between 67 and 71 inches tall? Round to 4 decimal places. PART 2: For a sample of 36 18-year-old men, what is the probability that the average of their heights is between 67 and 71 inches? Round to 4 decimal places. PART 3: What sample n would be necessary in order to have P(67 < x̄ < 69) = 0.95 Round to the nearest whole number.
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The heights of 18-year-old men are approximately normally distributed, with mean 68 inches and standard deviation 3 inches (based on information from Statistical Abstract of the United States, 112th Edition). (a) What is the probability that an 18-year-old man selected at random is between 67 and 69 inches tall? (b) If a random sample of nine 18-year-old men is selected, what is the probability that the mean height x is between 67 and 69 inches? (c) Interpretation Compare your answers to parts (a) and (b). Is the probability in part (b) much higher? Why would you expect this?

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Transcript

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00:01 Hey there, welcome to numerate.
00:03 We are asked to find a probability that an 18 -year -old man is between 67 and 71 inches tall, given that we're given the population standard deviation and mean here.
00:18 So let's write them down.
00:20 The mean that we're given here is equal to 68, and our standard deviation equals to 3.
00:36 All right, so we have 68 and 3 as our parameters here.
00:49 Now we are going to be using these two values here to solve for our probability.
01:01 So our first part here, part one, asks us to find a probability that x is between 67 and 71 inches tall.
01:16 So in order to find this probability here, what we would have to find and do is to expand this probability.
01:28 So we can expand this out into the probability where x is less than 71 minus the probability where x is less than 67.
01:49 So we're going to set up z -score equations for both of these.
01:53 We have our 71 minus 68 which is 3 3 divided by 3 equals 1 so with a z score of 1 we get a probability of around 0 .84134 and this is going to be subtracted to our other probability here where we have the z score of 70 67 minus 68 divided by 3 equaling negative 1 3rd to negative 0 .33.
02:28 And for this here, this gives us a c score that equals around for 67 of 0 .36944.
02:51 So we subtract giving us an in -between probability of around 0 .4719.
03:15 0 .4719.
03:19 Alright, so our next one here is part two.
03:30 So part two will be pretty similar here, but now we're giving a sample size of 36.
03:36 So we're still trying to find the probability, where now x mean is between 67 and 71.
03:58 So this basically equals the difference between the two probabilities.
04:05 So it's exactly same as above, but we're dealing with x bar x meet.
04:14 So to find the z scores now, we can do a shortcut method.
04:24 Z score equals our positive 1 from above multiplied by the square root of 36.
04:33 So this here will basically be 6 times 1, which is 6.
04:38 For this c score here, we're going to do the same, negative 0 .33, multiplied by the square root of 36.
04:53 All right, so with this here, we have a c score of 6, which corresponds to a probability of basically 1...
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