The helicopter view in the figure below shows two people...

The helicopter view in the figure below shows two people pulling on a stubborn mule. (Take F1 = 126 N and F2 = 67.0 N.) y F2 F1 75.0° 60.0° x (a) Find the single force that is equivalent to the two forces shown. magnitude N direction ° counterclockwise from the +x-axis (b) Find the force a third person would have to exert on the mule to make the net force equal to zero. magnitude N direction ° counterclockwise from the +x-axis

Transcript

00:01 Now in this problem we are given with this figure and the magnitude of this f1 force we have a 126 newton and f2 force we have this is 67 .0 newton now there are two parts in this question that we need to solve in the a part we need to find the single force that is equivalent to the two forces shown in this figure so to find that single force we'll go into resolve these two forces in the x and in the y component so that would be the x component for the f1 force and this would be the y component similarly for this force this would be the x component and this would be the y component so this is f1 x this is f1y the y component similarly this is f2x and f2y correct so i can write him the f1 force as a sum of the x component and the y component so f1 x i cap i cap is the unit vector along the x direction plus f1 y cap j cap is the unit vector along the y direction so f1 y so that would be f1 cosine 60 degrees and f1 we have 126 newton so 126 cosine 6 60 degrees i cap plus 126 sine 60 degrees j cap now on solving you'll get this value to be this would be 63 i cap and this would be 63 root 3 j cap now similarly we can represent the f2 vector in the x in the y component so f2 would be f2 x i cap plus f2y jcap right so that would become this would be now this is along the negative x so we'll be taking minus 67 cosine 75 degrees i cap plus this would be 67 sine 75 degrees j cap and on solving you'll get this value to be minus 17 .34 this is i cap plus this would be 64 .71 jcap now to find the single force equivalent to f1 and f2 we know that that force would be the vector sum of the first force plus the second force so f1 we have this thing 63 i cap plus 63 square root 3 like this is j cap then plus this is minus 17 .34 i cap plus 64 .7 j cap now we can add the x component with the x component and the y component with the y component so on adding you will get the force f to be equals to 45 point 6 i cap plus 173 0 .83 j cap but we have to find a magnitude so magnitude of this force will be square root 45 .66 square plus 173...

Question

Please give Ace some feedback