3 \, cm = 0.753 \, m$, and the length of the wires is $l = 49.9 \, m$. The force between two parallel wires carrying current is given by:
$$F = \frac{\mu_0 I_1 I_2 l}{2 \pi r}$$
where $\mu_0 = 4\pi \times 10^{-7} \, T \cdot m/A$ is the permeability of free space,
Show more…