00:03
Hi there.
00:03
In this question, we have this picture here where we see three of the blue n2 molecules and four of the red o2.
00:22
And we have a few questions about this.
00:24
The first one we want to know is what is the limiting reagent? well, we see that these react in a 1 to 2 ratio.
00:31
There's no coefficient in front of the nitrogen, so it's understood it's a 1.
00:35
So it's a 1 to 2 ratio.
00:39
So that means we need twice as many oxygen as we have nitrogen.
00:44
And we have three nitrogen.
00:47
So that means we would need six oxygen if we're going to have that one to two ratio.
00:54
So therefore, this tells us that the oxygen is the limiting reagent.
00:59
It's the one we're going to run out of first.
01:06
And therefore, it is the one that is going to determine how much product we can make and how much of the other reagent is going to be used.
01:16
So the limiting reagent is oxygen.
01:21
And next we want to calculate the number of no2 molecules.
01:25
So we have four o2 molecules.
01:34
And looking at the equation, we see a 2 -2 ratio between oxygen and nitrogen...