The index of refraction of benzene is $1.8$. What is the critical angle for a light ray traveling in benzene toward a plane layer of air above the benzene?
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Step 1: Recall the formula for critical angle in terms of the refractive indices: \( \sin \theta_C = \frac{1}{n} \), where \( n \) is the ratio of the refractive index of air to the refractive index of benzene. Show more…
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