The vibrational frequency \( \nu \) is related to the force constant \( k \) and the reduced mass \( \mu \) by the formula:
\[ \nu = \frac{1}{2\pi} \sqrt{\frac{k}{\mu}} \]
Given that the wavenumber \( \tilde{\nu} \) is 3961.64 cm\(^{-1}\), we can convert this
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