00:01
Really, to determine the limiting reactant, we first need to determine the maximum amount of grams of d - of ddt that each reactant can produce.
00:10
Whichever one produces the least amount, that will be the limiting reactant, and that will give us the answer to part a.
00:19
So we'll start with the 10 grams of chloral, convert it into moles using its molar mass, and then convert the moles, chloral, into moles, ddt, seeing it's a one -to -one mole relationship.
00:35
Once we have moles, ddt, that the chloral can pr - can produce, we'll multiply that by the molar mass of ddt in order to get grams.
00:46
So if all of the chloral were to react, we would get whatever this value is right here.
00:52
We'll perform a similar calculation to determine the mass of ddt that 10 grams of chloral benzene can produce.
01:01
We divide that by its molar mass to get moles, and then convert the moles, chloral benzene, 2, into the moles of ddt, 1.
01:10
And then again, once we have moles, we multiply by the molar mass.
01:14
So if all the chloral can react, we'd get 24 .05 grams ddt, and if all of the chloral benzene can react, we would get 15 .75 grams ddt.
01:26
Well, we're not gonna get the 24 .05 because we're gonna run out of chloral benzene, that being our limiting reactant, when we've made a theoretical yield of 15 .75.
01:39
So this is the answer to part c, 15 .75, and the limiting reactant is chloral benzene...