Question

The intensity, or loudness, of a sound can be measured in decibels (dB), according to the equation $I(dB) = 10logleft[frac{I}{I_0} ight]$, where $I$ is the intensity of a given sound and $I_0$ is the threshold of hearing intensity. What is the intensity, in decibels, $[I(dB)]$, when $I = 10^8(I_0)$?

          The intensity, or loudness, of a sound can be measured in decibels (dB), according to the equation $I(dB) = 10logleft[frac{I}{I_0}
ight]$, where $I$ is the intensity of a given sound and $I_0$ is the threshold of hearing intensity. What is the intensity, in decibels, $[I(dB)]$, when $I = 10^8(I_0)$?

$The intensity, or loudness, of a sound can be measured in decibels (dB), according to the equation I(dB) = 10logleft[fracII0 ight], where I is the intensity of a given sound and I0 is the threshold of hearing intensity. What is the intensity, in decibels, [I(dB)], when I = 10^8(I0)?$

Added by Tanya C.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Donna Densmore

07/19/2023

Step 1

We are given that I = 10 * I₀. We need to find the intensity in decibels, I(dB). Now, let's substitute the given value of I into the equation: I(dB) = 10 * log(10 * I₀ / I₀) Show more…

Show all steps

Thanks for your feedback!

The intensity, or loudness, of a sound can be measured in decibels (dB), according to the equation I(dB) = 10 * log(I/I0), where I is the intensity of a given sound and I0 is the threshold of hearing intensity. What is the intensity, in decibels (I(dB)), when I = 10^8(I0)?