Question

The ionic salt KBr is dissolved in water, much like the experiments given in the simulation. A mass of 71.0 g of salt is added to 100. g of water. Both start at a temperature of 23.0 ∘C. ΔHsoln for KBr is 8.00 kJ/mol . Given this information, calculate the final temperature (Tf).

Name: the ionic salt kbr is dissolved in water much like the experiments given in the simulation a mass of 710 g of salt is added to 100 g of water both start at a temperature of 230 c hsoln for k 19615
Uploaded: 2022-01-24T11:32:55-08:00
Duration: 1 min 26 s
Channel: Chittaranjan Sahoo
Description: the ionic salt kbr is dissolved in water much like the experiments given in the simulation a mass of 710 g of salt is added to 100 g of water both start at a temperature of 230 c hsoln for k 19615

          The ionic salt KBr is dissolved in water, much like the
experiments given in the simulation. A mass of 71.0 g of salt is
added to 100. g of water. Both start at a temperature of 23.0 ∘C.
ΔHsoln for KBr is 8.00 kJ/mol . Given this information, calculate
the final temperature (Tf).

Added by Sarah B.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Chittaranjan Sahoo

01/24/2022

Step 1

0 g of KBr is dissolved in water. Given: ΔHsoln = 8.00 kJ/mol Molar mass of KBr = 119 g/mol First, calculate the moles of KBr: 71.0 g / 119 g/mol = 0.596 moles Next, calculate the heat released: Q = ΔHsoln * moles Q = 8.00 kJ/mol * 0.596 mol = 4.768 kJ Show more…

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The ionic salt KBr is dissolved in water, much like the experiments given in the simulation. A mass of 71.0 g of salt is added to 100. g of water. Both start at a temperature of 23.0 ∘C. ΔHsoln for KBr is 8.00 kJ/mol . Given this information, calculate the final temperature (Tf).