00:01
Hello students, let's solve this problem.
00:02
The problem says the national center of the health statistics report that the psychotic black passer of the males 35 to 44 years of age has mean 128 and the standard deviation is equal to 15.
00:33
The medical directors of the large company look at the the medical record of the 72 executive in the age group and find that the mean of the serenitic black passer is in the sample is 126 .07.
00:59
At alpha is equal to 1 % is the evidence that the company executive have the different mean black from the population mean.
01:11
So we have to solve this problem.
01:14
So the information is given as follows, the national health center.
01:18
So the age group is given.
01:20
So mu is given, that is of 120, standard deviation, sigma is given here 15, and the sample size n is equal to 72.
01:31
So the sample mean of the cycotic black pressure, that is of x bar, is equal to 126 point of and the level of the significance alpha is equal to 0 .01.
01:48
Now the hypothesis is given as follows the null hypothesis that is 8 -0, the mean of the cellotic black pressure of the male 35 to 44 yards of the age 128.
02:01
So we can write down that 80 of mu, that is equal to 128 and ha, of mu that is not equal to of 128.
02:16
Next is we have to solve this problem, that is the formula you know, that is j is equal to x bar minus mu divided y of sigma divided by of rooted.
02:31
So you put all those values, so 126 .07 minus 128 divided by 15 divided by 15 divided by root of 72...