00:01
Hello students, let's solve this problem.
00:02
The problem says the joint density function capital x and y is given as f of x comma of y, that is integration, that is the part, not integration, the values is 24xy for 0 less than equal to x less than equal to 1, 0 less than equal to y, 0 less than equal to y, less than equal to y, less than equal to, 1, 0 less than equal to x plus y less than equal to 1.
00:37
And 0 is elsewhere.
00:44
So the first question is verify that f of xy is intent a joint probability distribution function so that we can find out f of x of x that is equal to 8 x of x and f of y of y that is is equal to three of y of y of y so x y are independent so now we move to the second question that find the density function of x so density function that is the formula of e of x is equal to integration 0 to 1 .8.
01:33
Of x of x of d x so that is after calculating you get here 8 now we move to the third question that is find the density function of y so find the density function so e of so we can say that is of e of y that is equal to integration 0 to 1 3y of y of d .y.
02:09
So this result you get here that is of three.
02:14
This result you get here that is of three.
02:18
So we can find out that the variance of x that is of e of x square minus of e of x whole square.
02:31
So this value is integration 0 to 1 8xx whole square of dx minus of 8...