00:01
Hello students in this question given f of x, y is equal to 3xy square by 0 less than or equal to x less than or equal to y less than or equal to 1 and 0 otherwise.
00:16
So we know that integral over 0 to 1 and here x to 1 f of x, y dy dx is equal to 1.
00:32
So now integrating 0 to 1 x to 1 pxy square dy dx is equal to 1 integral over 0 to 1 pxy cube divided by 3 x to 1 px is equal to 1.
00:54
So now taking the constant outside 0 to 1 x 1 divided by 3 minus x cube divided by 3 that means applying the limits here equal to 1.
01:06
So now integrating this term.
01:09
So see x square divided by 6 minus x power 5 divided by 15 will be equal to 1 here 0 to 1.
01:20
So now applying the limits here c 1 by 6 minus 1 divided by 15 is equal to 1.
01:26
So the value of c is 10 and next f of x is equal to x to 1 10 x y square dy.
01:44
So that is equal to 10 x y cube divided by 3 here x to 1 that is equal to 10 x divided by 3 1 minus x cube and next f of y.
02:05
So that is f of y equal to 0 to y 10 x y square dx.
02:13
So that is 10 y square into x square divided by 2 0 to y.
02:20
So that is equal to 5 y cube and next we know that x and y are independent if f of x comma y is equal to f of x into f of y.
02:43
So now substituting the values here 10 x divided by 3 into 1 minus x cube into 5 y cube...