The joint probability distribution of two random variables...

The joint probability distribution of two random variables X, Y is given in the table below. Value of Y -4 -2 1 Value of X -4 .07 .01 .11 -3 .04 .06 .00 -1 .18 .00 .17 0 .00 .03 .07 2 .24 .02 .00 From the information in the table, calculate each of the following probabilities. Round your answers to two decimal places. a. Given that Y = -4, compute the probability that X = 2. b. Given that X ? -3, compute the probability that Y > -2.

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Transcript

00:01 Hello, students, welcome.

00:01 We have a question here.

00:03 And in this question, we have a table.

00:07 And this is about the value of x, value of x and next parameter is value of y.

00:19 So we are having three, we are here to find the three probability questions.

00:26 So let's start solving this question.

00:28 Here, in this question, the given, the given, joint pmf, joint pmf of x and y, we have to make a table for it as where i am showing you.

00:52 So this will be the table format and here we will write x obliq y.

00:59 Next column will be for minus 3.

01:01 Then we have 0.

01:02 After that we have one then two then four and last for probability xpx and our first observation value is minus two at three it is value is 0 .07 0 this is equal to 0 .13 at 2 it is 0 .15 next is 0 .18 next is 0 .08 and then it is equal to 0 .59.

01:35 Then for 2, this would be a 0 .11.

01:40 Next is 0 .17.

01:43 Next one is 0 .02.

01:46 Then we have 0 .04.

01:49 Next the view is 0 .00.

01:52 Then 0 .3.

01:56 Next is 4 for xobdified.

02:00 And here we will have 0 .01.

02:02 Next value is 0 .00.

02:05 Next is 0 .04.

02:08 Then we have 0 .02...

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