00:01
So in this question we're told that the joint pmf for x and y is f of x and y is c xy for x equals 1 2 3 and y equals 1 2 3 and 0 otherwise.
00:21
So first of all we want to find the constant c and that means that the sum of x and y of f of x and y should be equal to 1 because it's a probability.
00:30
So 1 is equal to c times the sum from x equals 1 to 3 of x times the sum from y equals 1 to 3 of x times the sum from y equals 1 to 3 of sorry no that's not right x y and then we want a sum from y equals 1 to 3 of that as well.
01:05
So the sum of x from x from y equals 1 to 3 of that as well.
01:07
To 3 is going to be, so we've got c, the sum from 1 to 3, 1 plus 2 plus 3 is 6.
01:13
So sum from y equals 1 to 3 of 6 y.
01:17
But we know the sum from 1 to 3 is 6.
01:21
So this gives us 36 c.
01:24
So c is 1 over 36.
01:28
So we have f of x and y is 1 over 36 x y, x y equals 1, 2, 3.
01:39
So now, probability that x equals 2 and y equals 3 is 1 over 36 2 times 3, 6 over 36 or 1 6th.
01:54
The probability that 1 less than x less than or equal to 2, y less than equal to 2 is going to be the sum from x equals 1 to 2, of 1 over 36 xy.
02:16
So this is going to be 1 over 36 times the sum from x equals 1 to 2.
02:21
And then 1 plus 2 is 3, so 3x.
02:26
So this is going to be 9 over 36.
02:29
And if we divide by 3, we can get 3 over 12, and we can divide by 3 again to get a quarter.
02:39
So now part d, probability that x is greater than equal to 2 is going to be the sum from y equals 1 to 3, sum from x equals 2 to 3, 1 over 36 xy...