Given:
Volume of potassium benzoate solution (V1) = 49.5 mL = 0.0495 L
Volume of benzoic acid solution (V2) = 50.5 mL = 0.0505 L
Molarity of potassium benzoate (M1) = 0.98 M
Molarity of benzoic acid (M2) = 1.01 M
Calculate the concentration of benzoate ion:
\[
Show more…