The Kf values for formation of [Cu(NH3)4]2+and [Cu(en)2]2+ are given below. Explain the difference in the values [Cu(NH3)4]2+ Kf=1.1×1013 [Cu(en)2]2+ Kf=1.0×1020
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A higher Kf value means a more stable complex ion. Show more…
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The Kf for [Cu(en)2]2+ is much larger than the one for [Cu(NH3)4]2+. This difference is primarily an entropy effect. Explain why and calculate the difference between the S values at 298 K for the complete dissociation of the two complex ions. (Hint: The value of H is about the same for both systems.)
The complex ion Cu(NH3)42+ is formed in a solution made of 0.0500M Cu(NO3)2 and 0.300M NH3. What are the concentrations of Cu2+, NH3, and Cu(NH3)42+ at equilibrium? The formation constant*, Kf, of Cu(NH3)42+ is 1.70 × 1013. [Cu2+]= [NH3]= [Cu(NH3)2+4]+
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The complex ion Cu(NH3)42+ is formed in a solution made of 0.0400 M Cu(NO3)2 and 0.400 M NH3. What are the concentrations of Cu2+, NH3, and Cu(NH3)42+ at equilibrium? The formation constant, Kf, of Cu(NH3)42+ is 1.70 x 10^13. [Cu2+] = .04 M [NH3] = 0.24 M [Cu(NH3)42+] = 7.09 x 10^-13 M
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