00:01
Which most nearly gives the furthest distance a 75 -kilogram man could climb up the ladder.
00:07
So our force of friction at point a, force f1, is equal to mu times normal 1, and f at 2 is mu n2.
00:19
For equilibrium, the sum of all of our forces in the y direction is equal to 0.
00:25
So we have n1 minus 75g minus 35g minus 35 times g.
00:31
Plus fff2 is equal to 0.
00:36
So this results in n1 plus mu n2 is equal to 1079 .1.
00:44
Now in the x direction, we get mu n1 minus n2 is equal to 0.
00:52
So from here, we get n1, or n2, is equal to 0 .25n1.
01:02
So we can plug these in.
01:04
We have n1 plus 0 .25 .1.
01:06
25 times 0 .25 n1 is equal to 1079 .1.
01:14
And so n1 is equal to 101 .5 .6 newtons.
01:19
And n2 is 253 newtons.
01:25
Now our next step is we'd like to find our distance...