00:01
I am a teacher for this question and our question says that the length of a rectangle is 5 yard less than twice the width and the area of the rectangle is 33 yard square, find the dimensions of the rectangle.
00:13
So the length of a rectangle is 5 yard less than its width.
00:18
Let width of rectangle be x yards and the length will become how much the length will become 5 yard less than twice the widths, 5 yard less than twice the widths.
00:40
So what i'll be writing out is that the area is 33 yard square.
00:45
So area is set to be close to 33 yard square.
00:48
So length into width, so 2x minus 5 times x as to be goes to 33.
00:55
So i'll be writing this as that 2x square minus of 5x minus of 33 equals to 0.
01:04
So, 33, 26, so 11x are 66.
01:08
So 2x squared minus of 11x plus of 6x minus 33 equals to 0.
01:15
So i'll be taking x as a common 2x minus 11 here plus of 3 as a common 2x minus 11 here and that is equal to 0...