00:01
This problem says the length of a rectangle is 7 less than twice the length of its width.
00:04
If the area of the rectangle is 15 square meters, find the value of x.
00:09
And our assumption here is that the value of x will be one of our dimensions, either length or width, that we use to represent this expression for area, because we know that area is length times width, and we are not given anything about the length or width other than what the length is with the comparison to the width.
00:27
So what we will do is say that our width is x, that way we can define our length in terms of x, because we are told that our length is 7 less than twice the width.
00:38
And twice the width here would be 2x, and if our length is 7 less than that, then our length would be 2x minus 7.
00:46
And now we have both of these in terms of x, so we can show that our length times width are 2x minus 7 times x, which would distribute our x to give us 2 squared minus 7x, which is supposed to be equal to our area, which was 15 meters squared...