The length of time patients must wait to see a doctor in a local clinic is uniformly distributed between 45 minutes and 2 1 2 hours. (a) What is the probability of a patient waiting exactly 55 minutes? (b) What is the probability that a patient would have to wait between 65 minutes and 2 hours? (Round your answer to two decimal places.) (c) Compute the probability that a patient would have to wait over 2 hours. (Round your answer to two decimal places.) (d) Determine the expected waiting time and its standard deviation (in minutes). (Round your standard deviation to two decimal places.) E(x) = min σ = min
Added by Deborah P.
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In this case, alpha = 45 and beta = 150. Therefore, the probability is 1/(150 - 45) = 1/105 = 0.0095. Show more…
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