00:01
Alright, so for this question we've got a normal distribution with a mean of 194 and a standard deviation of 7 .2, and we're told that 49 individuals are randomly chosen, so that's n equals 49.
00:13
First we want to know what is the distribution of x bar.
00:17
So the distribution of x bar is going to also be normally distributed with the same mean as the original, but then with a standard deviation of sigma divided by the square root of n.
00:34
So if we're putting that to two decimal places, 7 .2 divided by the square root of 49 is 1 .0286.
00:52
Okay, so that would be the standard deviation.
00:55
So now for this sample size, i'm going to find the probability that the average hand length is more than 196.
01:04
So to do that we're going to compute a z score.
01:09
Z is the mean that i'm looking for minus the mean from the population divided by the standard deviation of the sampling distribution, which is that 1 .0286.
01:22
So this is going to be 196 minus 194 over 1 .0286.
01:30
So when i take that, 2 divided by 1 .0286, i get 1 .9443 or 444.
01:46
So now i need to look up that on my z chart.
01:54
Okay, i need to look up 1 .94.
01:56
I need to find the 1 .944.
02:04
I need to find the probability that it's above that...