Question

The likelihood that a patient with a heart attack dies of the attack is 0.04 (i.e., 4 of 100 die of the attack). Suppose we have 5 patients who suffer a heart attack, what is the probability that all will survive? calculate the answer in 2 decimal place. Round off the answer. 0.82 $5! \times (0.96)^5$ $0.04 \times (0.96)^5$ $5 \times (0.96)^5$

          The likelihood that a patient with a heart attack dies of the attack is 0.04 (i.e., 4 of 100 die of the attack).
Suppose we have 5 patients who suffer a heart attack, what is the probability that all will survive? calculate the answer in 2 decimal place. Round off the answer.
0.82
$5! \times (0.96)^5$
$0.04 \times (0.96)^5$
$5 \times (0.96)^5$

The likelihood that a patient with a heart attack dies of the attack is 0.04 (i.e., 4 of 100 die of the attack).
Suppose we have 5 patients who suffer a heart attack, what is the probability that all will survive? calculate the answer in 2 decimal place. Round off the answer.
0.82
5! × (0.96)^5
0.04 × (0.96)^5
5 × (0.96)^5

Added by Nancy L.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Hubert Agamasu

03/22/2022

Step 1

04 = 0.96. Show more…

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The likelihood that a patient with a heart attack dies of the attack is 0.04 (i.e.,4 of 100 die of the attack) Suppose we have 5 patients who suffer a heart attack what is the probability that all will survive? calculate the answer in 2 decimal place. Round off the answer. O0.82 O5!(0.96)5 O 0.04 x (0.96)5 O5 (0.96)5